7. Elements of group 16,17,18 12
Elements of group 16, 17, 18 CET MCQ
Chemistry | MHT-CET Previous year questions with detailed solutions
MHT-CET 2014
Q1. What is the geometry of a molecule of bromine pentafluoride?
Solution:
- In BrF5, the central Bromine atom has 7 valence electrons.
- It forms 5 sigma bonds with 5 Fluorine atoms.
- Number of lone pairs = (7 - 5) / 2 = 1 lone pair.
- Total electron pairs (Steric Number) = 5 (bond pairs) + 1 (lone pair) = 6.
- The hybridization is sp3d2. According to VSEPR theory, 6 electron pairs with 1 lone pair results in a Square pyramidal geometry.
MHT-CET 2014
Q2. Ozone is present as a chief constituent in which region of the atmosphere?
Solution:
- The atmosphere is divided into layers: Troposphere, Stratosphere, Mesosphere, and Thermosphere.
- The ozone layer (ozonosphere) is located within the Stratosphere, approximately 15 to 35 kilometers above the Earth's surface.
- It acts as a shield, absorbing the majority of the Sun's harmful ultraviolet (UV) radiation.
MHT-CET 2015
Q3. What is the most abundant element on earth?
Solution: Oxygen is the most abundant element in the Earth's crust (approx. 46.6% by mass) and the second most abundant in the atmosphere.
MHT-CET 2015
Q4. Which halogen forms an oxyacid that contains the halogen atom in tripositive oxidation state?
Solution: Chlorine forms Chlorous acid (HClO2). Calculation: (+1) + x + 2(-2) = 0 ⇒ x = +3. This is the tripositive (+3) state.
MHT-CET 2015
Q5. Electronic configuration of only one p-block element is exceptional. One molecule of that element consists of how many atoms of it?
Solution: Helium (He) is the p-block element with an exceptional configuration (1s2) because it has no p-electrons but is placed in Group 18. Noble gases are monoatomic, meaning one molecule contains one atom.
MHT-CET 2015
Q6. Identify a metalloid from the following list of elements.
Solution: Tellurium (Te) is a metalloid. Carbon is a non-metal, Neon is a noble gas (non-metal), and Sodium is an alkali metal.
MHT-CET 2016
Q7. The most abundant noble gas in atmosphere is
Solution: Argon is the most abundant noble gas in the Earth's atmosphere, making up approximately 0.93% of the air by volume.
MHT-CET 2016
Q8. What is the highest oxidation state exhibited by group 17 elements?
Solution: Group 17 elements (Halogens) have 7 valence electrons (ns2 np5). They can exhibit a maximum oxidation state of +7, as seen in compounds like IF7 or HClO4.
MHT-CET 2016
Q9. The element that does NOT form acidic oxide is
Solution: Barium is an alkaline earth metal. Metal oxides are generally basic. Barium oxide (BaO) is a basic oxide, whereas oxides of non-metals like C, P, and Cl are acidic.
MHT-CET 2017
Q10. Which halogen has the highest value of negative electron gain enthalpy?
Solution: Although Fluorine is more electronegative, Chlorine has the highest negative electron gain enthalpy. This is because Fluorine's small size leads to high inter-electronic repulsion when an electron is added.
MHT-CET 2017
Q11. Which among the following compounds does NOT act as a reducing agent?
Solution: Reducing character increases down the group for Group 16 hydrides (H2O < H2S < H2Se < H2Te) as the M-H bond strength decreases. H2O is the most stable and does not act as a reducing agent.
MHT-CET 2017
Q12. Which element among the following does NOT form diatomic molecules?
Solution: Argon is a noble gas with a complete octet. It exists as monoatomic atoms (Ar). Oxygen (O2), Nitrogen (N2), and Bromine (Br2) all exist as diatomic molecules.
MHT-CET 2019
Q13. The CORRECT decreasing order of energy released when an electron is added to neutral gaseous halogens is
Solution: Chlorine has a higher negative electron gain enthalpy than Fluorine due to less inter-electronic repulsion in its larger 3p orbital compared to Fluorine's compact 2p orbital. The general trend then decreases down the group.
MHT-CET 2020
Q14. Which among the following halogen does NOT form polyhalide ion?
Solution: Fluorine does not have vacant d-orbitals in its valence shell to expand its octet, and its high electronegativity prevents it from acting as a central atom in polyhalide ions like I3- or Br3-.
MHT-CET 2020
Q15. Which among the following pairs of halogen forms the interhalogen compound of the type XX'7?
Solution: The only known interhalogen compound of the type XX'7 is IF7 (Iodine Heptafluoride). This is possible because Iodine is large enough to accommodate seven small Fluorine atoms around it.
MHT-CET 2020
Q16. What is the highest oxidation state possessed by chlorine in its oxyacids?
Solution: In Perchloric acid (HClO4), Chlorine exhibits its maximum oxidation state of +7. Calculation: (+1) + x + 4(-2) = 0 ⇒ x = +7.
MHT-CET 2021
Q17. Which of the following oxoacids of sulphur is called as pyrosulphuric acid?
Solution: H2S2O7 is Pyrosulphuric acid, commonly known as Oleum. It is produced by dissolving SO3 in concentrated H2SO4.
MHT-CET 2021
Q18. Which among the following reactions is used to prepare oleum?
Solution: The reaction of Sulphur trioxide with concentrated Sulphuric acid yields H2S2O7, which is Oleum.
MHT-CET 2021
Q19. What is the number of lone pair of electrons in IF7?
Solution: Iodine has 7 valence electrons. In IF7, it forms 7 sigma bonds with 7 Fluorine atoms. Lone pairs = (7 - 7) / 2 = 0. The geometry is pentagonal bipyramidal.
MHT-CET 2021
Q20. Which among the following is a colourless gas?
Solution: IF7 is a colourless gas at room temperature. ICl is a ruby red solid, ICl3 is an orange-yellow solid, and BrF3 is a yellowish-green liquid.
MHT-CET 2021
Q21. Which of the following elements does NOT form gaseous hydride at room temperature?
Solution: The hydride of oxygen is H2O (Water), which is a liquid at room temperature due to extensive intermolecular hydrogen bonding. Hydrides of Se, Te, and S (H2Se, H2Te, H2S) are all gases.
MHT-CET 2021
Q22. What is O-O bond length in resonance hybrid of ozone?
Solution: In Ozone (O3), the two O-O bonds are identical due to resonance. The bond length is 128 pm, which is intermediate between a single bond (148 pm) and a double bond (121 pm).
MHT-CET 2021
Q23. Identify metal halide from following having highest ionic character. (M = metal atom)
Solution: According to Fajan's rules, ionic character is highest when the anion is small. Since Fluoride (F-) is the smallest anion among the halogens, MF has the highest ionic character.
MHT-CET 2021
Q24. Identify the use of mixture of Ar and N2 from following.
Solution: A mixture of Argon and Nitrogen is used in electric bulbs to provide an inert atmosphere, preventing the oxidation and evaporation of the tungsten filament.
MHT-CET 2021
Q25. Which element from following belongs to oxygen family?
Solution: The oxygen family (Group 16) consists of Oxygen (O), Sulphur (S), Selenium (Se), Tellurium (Te), and Polonium (Po). Therefore, Selenium (Se) is the correct answer.
MHT-CET 2021
Q26. Which among the following compounds is NOT a colourless gas?
Solution: ClF3 (Chlorine trifluoride) is a colourless gas at very low temperatures but is typically encountered as a pale-greenish yellow liquid at room temperature. ClF and IF7 are colourless gases.
MHT-CET 2022
Q27. Identify the product obtained when sucrose is treated with conc. H2SO4.
Solution: Concentrated H2SO4 is a powerful dehydrating agent. It removes water molecules from sucrose (C12H22O11), leaving behind a black mass of carbon known as sugar charcoal.
MHT-CET 2022
Q28. What is the quantity of sugar charcoal obtained when 34.2 g sugar is charred using required quantity of conc. sulphuric acid under ideal conditions?
Solution: Reaction: C12H22O11 → 12C + 11H2O.
Molar mass of Sucrose = 342 g/mol. Molar mass of 12 Carbon atoms = 12 × 12 = 144 g.
Since 342 g of sugar gives 144 g of charcoal, 34.2 g of sugar will give (144 / 342) × 34.2 = 14.4 g.
Molar mass of Sucrose = 342 g/mol. Molar mass of 12 Carbon atoms = 12 × 12 = 144 g.
Since 342 g of sugar gives 144 g of charcoal, 34.2 g of sugar will give (144 / 342) × 34.2 = 14.4 g.
MHT-CET 2022
Q29. What are the different elements present in mineral baryte?
Solution: Baryte (or Barite) is a mineral consisting of Barium sulphate (BaSO4). Therefore, the elements present are Barium (Ba), Sulphur (S), and Oxygen (O).
MHT-CET 2022
Q30. Which of following interhalogen compounds is NOT obtained by action of fluorine with bromine? (X = Br, X' = F)
Solution: Bromine forms BrF, BrF3, and BrF5. However, it cannot form BrF7 (XX'7 type) because the Bromine atom is not large enough to accommodate seven Fluorine atoms. Only Iodine forms the XX'7 type (IF7).
MHT-CET 2022
Q31. Which among the following compounds contains highest number of chlorine atoms in their single molecule?
Solution:
Phosgene: COCl2 (2 Cl atoms).
Tear gas (Chloropicrin): CCl3NO2 (3 Cl atoms).
Mustard gas: (ClCH2CH2)2S (2 Cl atoms).
Phosphine: PH3 (0 Cl atoms).
Tear gas has the highest number.
Tear gas (Chloropicrin): CCl3NO2 (3 Cl atoms).
Mustard gas: (ClCH2CH2)2S (2 Cl atoms).
Phosphine: PH3 (0 Cl atoms).
Tear gas has the highest number.
MHT-CET 2022
Q32. Identify phosphorus containing salt from following.
Solution: Fluorapatite is a phosphate mineral with the formula 3Ca3(PO4)2·CaF2. It is a major source of phosphorus.
MHT-CET 2022
Q33. Which element from following is most electronegative?
Solution: Electronegativity values (Pauling scale): O (3.44), Cl (3.16), Br (2.96). Oxygen is the second most electronegative element in the periodic table after Fluorine.
MHT-CET 2022
Q34. Which among the following metal halides is highly covalent in nature?
Solution: According to Fajan's rules, a higher oxidation state of the metal leads to higher covalent character. In UF6, Uranium is in the +6 oxidation state, making it highly covalent.
MHT-CET 2022
Q35. Which of the following molecules is most polar?
Solution: Polarity depends on the electronegativity difference between the bonded atoms. Since Fluorine is the most electronegative element, the H-F bond has the greatest dipole moment and highest polarity.
MHT-CET 2022
Q36. Which element from the following has smallest atomic size?
Solution: Atomic size increases down a group and decreases across a period. Bromine (Period 4) is above Iodine (Period 5) and is to the right of Tellurium and Polonium, making it the smallest in this list.
MHT-CET 2022
Q37. What is the action of chlorine in excess ammonia?
Solution: When excess ammonia reacts with chlorine, the reaction is: 8NH3 + 3Cl2 → 6NH4Cl + N2. This produces ammonium chloride and nitrogen gas.
MHT-CET 2022
Q38. Which among the following elements does exhibit anomalous behaviour with its group elements?
Solution: Oxygen, being the first member of Group 16, shows anomalous behavior due to its small size, high electronegativity, and the absence of vacant d-orbitals in its valence shell.
MHT-CET 2022
Q39. Identify the different elements present in the mineral galena.
Solution: Galena is the primary ore of lead and consists of Lead(II) sulphide (PbS). Therefore, the elements present are Lead (Pb) and Sulphur (S).
MHT-CET 2022
Q40. Identify thiosulphuric acid from following.
Solution: The chemical formula for thiosulphuric acid is H2S2O3. It is an oxoacid of sulfur where one oxygen atom is replaced by a sulfur atom.
MHT-CET 2022
Q41. What is the number of moles of water removed from one mole of cane sugar when charred completely using conc. H2SO4?
Solution: The formula for cane sugar (sucrose) is C12H22O11. Dehydration removes all hydrogen and oxygen as water: C12H22O11 → 12C + 11H2O. Thus, 11 moles of water are removed.
MHT-CET 2022
Q42. Which from following activities results into the formation of oleum in manufacture of sulphuric acid by contact process?
Solution: In the Contact Process, Sulphur trioxide (SO3) is absorbed in concentrated Sulphuric acid (H2SO4) to form Oleum (H2S2O7).
MHT-CET 2022
Q43. Identify the molecular geometry of XeF4.
Solution: Xenon has 8 valence electrons. In XeF4, there are 4 bond pairs and 2 lone pairs. According to VSEPR theory, this results in an sp3d2 hybridization with a square planar molecular geometry.
MHT-CET 2022
Q44. Which among the following molecules has lowest bond dissociation enthalpy?
Solution: Bond dissociation enthalpy generally decreases down the group as atomic size increases and bond length increases. Iodine (I2) has the largest bond length and the weakest bond among the listed halogens.
MHT-CET 2022
Q45. Which among the following is group 16 element?
Solution: Group 16 (Chalcogens) includes Oxygen, Sulphur, Selenium, Tellurium, and Polonium (Po). Sb and As are in Group 15, and Pb is in Group 14.
MHT-CET 2022
Q46. Which of the following compounds is octahedral?
Solution: In SF6, Sulfur is bonded to 6 Fluorine atoms with zero lone pairs. This results in sp3d2 hybridization and a perfect octahedral geometry.
MHT-CET 2022
Q47. Identify the element from following that can exhibit -2, -1 and +2 oxidation states.
Solution: Oxygen exhibits -2 in most compounds (like H2O), -1 in peroxides (like H2O2), and +2 in its compound with fluorine (OF2).
MHT-CET 2022
Q48. Identify the element having smallest atomic radius from following.
Solution: In a period, atomic radius generally decreases from left to right. However, noble gases like Krypton (Kr) have a larger van der Waals radius than the preceding halogen. Therefore, Bromine (Br) is the smallest in this list.
MHT-CET 2022
Q49. Which among the following metal halides is weakly ionic in nature? (M = metal atom)
Solution: According to Fajan's rules, covalent character increases (and ionic character decreases) with an increase in the size of the anion. Since Iodide (I-) is the largest anion, MI is the most covalent and thus the most "weakly ionic."
MHT-CET 2023
Q50. Identify strongest oxoacid of halogen from following.
Solution: For the same central halogen atom, acidity increases with the increase in oxidation state. Perchloric acid (HClO4) has Chlorine in the +7 state, making it the strongest oxoacid.
MHT-CET 2023
Q51. Identify the method used to obtain SO2 gas in industry.
Solution: Industrially, SO2 is produced as a byproduct during the roasting of sulfide ores (like zinc blende or iron pyrites) in the presence of excess air.
MHT-CET 2023
Q52. Which from following is a CORRECT decreasing order of ionization enthalpies of different elements?
Solution: Ionization enthalpy decreases down the group due to an increase in atomic size and the shielding effect. Thus, the order for Group 16 is S > Se > Te > Po.
MHT-CET 2023
Q53. Which from following molecules exhibits lowest thermal stability?
Solution: In Group 16 hydrides, the M-H bond strength decreases down the group as the size of the central atom increases. Therefore, H2Te has the weakest bond and the lowest thermal stability.
MHT-CET 2023
Q54. Which noble gas element from following belongs to group 17 of periodic table?
Solution: All the options provided (Xe, Kr, Ar, Ne) are Noble Gases belonging to Group 18. Group 17 consists of Halogens (F, Cl, Br, I, At). Note: This question in the source may contain a typo asking for Group 18, or the intended answer is "None."
MHT-CET 2023
Q55. Identify FALSE statement from following.
Solution: This statement is false because Sulfur (S8) is a solid with higher intermolecular forces than Oxygen (O2), which is a gas. Therefore, the boiling point of Sulfur is much higher than that of Oxygen.
MHT-CET 2023
Q56. Which element from following does NOT belong to chalcogen family?
Solution: The chalcogen family consists of Group 16 elements (O, S, Se, Te, Po). Astatine (At) is a halogen belonging to Group 17.
MHT-CET 2023
Q57. Which from following is a CORRECT decreasing order of ionisation enthalpy for different elements?
Solution: Ionization enthalpy decreases down a group (Ne > Ar) and generally increases across a period (Cl > S). Noble gases have the highest values in their respective periods due to stable octet configurations.
MHT-CET 2023
Q58. Identify the element having positive electron gain enthalpy.
Solution: Noble gases like Neon have completely filled orbitals. Adding an extra electron is energetically unfavorable and requires energy, resulting in a positive electron gain enthalpy.
MHT-CET 2023
Q59. Which from following is a CORRECT decreasing order of ionization enthalpies of different elements?
Solution: Ionization enthalpy decreases down the group (Ar > Kr). Within the same period (Period 4), the value increases from left to right (Kr > Br > Se).
MHT-CET 2023
Q60. Which among the following statements is NOT correct about group-16 elements?
Solution: Due to the inert pair effect, the stability of the +6 oxidation state actually decreases down the group, while the +4 state becomes more stable.
MHT-CET 2023
Q61. Identify the element having anomalous behaviour as compared with other members of group.
Solution: Fluorine shows anomalous behavior due to its extremely small size, highest electronegativity, low F-F bond dissociation enthalpy, and absence of d-orbitals.
MHT-CET 2023
Q62. Which from following elements exhibits highest number of different oxidation states?
Solution: Tellurium, being a heavier chalcogen, can exhibit multiple oxidation states such as -2, +2, +4, and +6. Zn only shows +2, and As shows -3, +3, and +5.
MHT-CET 2023
Q63. Which among the following statements about dioxygen is NOT correct?
Solution: Dioxygen liquifies at 90 K and freezes at 55 K. Therefore, the statement that it liquifies at 55 K is incorrect.
MHT-CET 2023
Q64. Which of the following gases is used in current rectifiers?
Solution: A mixture of Neon and Helium is used in gas-filled current rectifiers and certain types of discharge lamps.
MHT-CET 2023
Q65. Identify the product obtained when elemental sulphur is treated with double quantity of hot conc. sulphuric acid.
Solution: The reaction is a comproportionation reaction: S + 2H2SO4 (conc.) → 3SO2 + 2H2O. Here, elemental sulphur is oxidized and the sulphur in sulphuric acid is reduced to sulphur dioxide.
MHT-CET 2023
Q66. Which of the following compounds is obtained when SO2 gas reacts with NaOH solution?
Solution: Sulphur dioxide reacts with sodium hydroxide to form sodium sulphite and water: SO2 + 2NaOH → Na2SO3 + H2O. If SO2 is in excess, it further forms NaHSO3.
MHT-CET 2023
Q67. What is the number of allotropic forms exhibited by oxygen and selenium respectively?
Solution: Oxygen has 2 main allotropic forms: Dioxygen (O2) and Ozone (O3). Selenium has multiple allotropes, typically recognized as 4 main forms: Red (monoclinic), Grey (hexagonal/metallic), Black (vitreous), and amorphous.
MHT-CET 2023
Q68. Identify the colour of I2 gas from following.
Solution: While Iodine is a lustrous greyish-black solid at room temperature, it sublimes on heating to form a characteristic violet-coloured gas.
MHT-CET 2023
Q69. Which from following statements is NOT correct?
Solution: This statement is incorrect. Argon is actually the most abundant noble gas in the atmosphere (approx. 0.93%). Radon or Helium/Xenon are among the least abundant.
MHT-CET 2023
Q70. What is oxidation state of halogen atom in perhalic acid?
Solution: Perhalic acids (like HClO4, HBrO4, HIO4) follow the general formula HXO4. The oxidation state calculation: (+1) + x + 4(-2) = 0 ⇒ x = +7.
MHT-CET 2023
Q71. Which element from following exhibits more than two allotropic forms?
Solution: Sulfur exhibits numerous allotropic forms, including Rhombic (alpha), Monoclinic (beta), and Plastic sulfur. Oxygen only has two (O2, O3). Sulfur is well known for having the most varied allotropy in this group.
MHT-CET 2023
Q72. Which element from following has positive electron gain enthalpy?
Solution: Noble gases like Argon have stable, fully filled valence shells. Adding an electron requires energy to be supplied, resulting in a positive electron gain enthalpy. Halogens and chalcogens release energy (negative enthalpy).
MHT-CET 2023
Q73. Which from following minerals has formula KCl·MgCl2·6H2O?
Solution: Carnallite is a hydrated double chloride of potassium and magnesium with the formula KCl·MgCl2·6H2O. It is an important source of potassium and magnesium.
MHT-CET 2023
Q74. Which element from following has lowest density?
Solution: Among the noble gases, density increases down the group as atomic mass increases faster than atomic volume. Helium (He) is the first member and has the lowest density.
MHT-CET 2023
Q75. Which from following molecules exhibits highest acidic nature?
Solution: In Group 16 hydrides, acidic strength increases down the group. This is because the H-E bond dissociation enthalpy decreases as the size of the central atom (E) increases, making it easier to release H+ ions.
MHT-CET 2023
Q76. Identify the element having general electronic configuration ns2np4 from following.
Solution: The configuration ns2np4 belongs to Group 16 (Chalcogens). Selenium (Se) is a member of Group 16. Bromine is Group 17 (np5), and Xenon/Krypton are Group 18 (np6).
MHT-CET 2023
Q77. Which from following elements is NOT radioactive?
Solution: Argon (Ar) is a stable noble gas. Astatine (At), Polonium (Po), and Radon (Rn) are all naturally radioactive elements.
MHT-CET 2023
Q78. Identify the element having highest density from following.
Solution: In Group 16, density increases down the group from Oxygen to Tellurium as atomic mass increases significantly compared to the increase in atomic volume.
MHT-CET 2023
Q79. Identify a molecule having lowest value of ∠H-E-H (consider E = O, S, Se, Te) from following.
Solution: The bond angle (H-E-H) decreases down the group. As the central atom becomes larger and less electronegative, the bond pairs move further away from the nucleus, resulting in less repulsion and a smaller angle. H2Te has the smallest angle (~90°).
MHT-CET 2023
Q80. Which from following characteristics for interhalogen compounds is NOT true?
Solution: This statement is false. Interhalogen compounds are all diamagnetic because they have an even number of valence electrons which are all paired up in the covalent bonds.
MHT-CET 2023
Q81. Which from following formulae is of galena?
Solution: Galena is the primary ore of lead, chemically known as Lead(II) sulphide (PbS).
MHT-CET 2023
Q82. Which from following elements belongs to group 17 of periodic table?
Solution: Group 17 elements are the halogens. Astatine (At) is the radioactive halogen at the bottom of Group 17.
MHT-CET 2023
Q83. Which element from following exhibits the highest number of allotropes?
Solution: Sulphur is known for having the largest number of allotropes among all elements in Group 16, including rhombic, monoclinic, plastic, and several other forms.
MHT-CET 2023
Q84. Which among the following compounds is a colourless gas at normal temperature?
Solution: Chlorine monofluoride (ClF) is a colourless gas at room temperature. ICl is a ruby-red solid, and IBr is a black crystalline solid.
MHT-CET 2023
Q85. What is the value of ∠S-S-S in puckered S8 rhombic sulfur?
Solution: In the puckered S8 ring of rhombic sulfur, the S-S-S bond angle is approximately 107°, and the S-S bond length is about 204 pm.
MHT-CET 2024
Q86. If A, B, C, D are four different elements with outer electronic configuration as A=4s24p4, B=4s24p5, C=5s25p4, D=5s25p5. Find the element having highest ionization enthalpy (ΔiH1).
Solution: Ionization enthalpy increases across a period and decreases down a group. Elements A and B are in Period 4, while C and D are in Period 5. Between A and B, B (halogen) has a higher value than A (chalcogen). Since Period 4 elements are smaller than Period 5, element B has the highest ionization enthalpy.
MHT-CET 2024
Q87. Identify the element having highest value of first ionization enthalpy.
Solution: Noble gases possess the highest ionization enthalpies in their periods due to stable octet configurations. Comparing Ar (Period 3) and Xe (Period 5), Argon is smaller and thus requires significantly more energy to remove an electron.
MHT-CET 2024
Q88. Identify thermally most stable hydrogen halide from following.
Solution: Thermal stability of hydrogen halides decreases down the group (HF > HCl > HBr > HI). As atomic size increases, the H-X bond length increases and bond dissociation enthalpy decreases. HF has the shortest, strongest bond.
MHT-CET 2024
Q89. Which from following group-16 elements has lowest negative electron gain enthalpy?
Solution: In Group 16, Oxygen has the lowest negative electron gain enthalpy. This is due to its exceptionally small size, which leads to high inter-electronic repulsion in its compact 2p subshell when an additional electron is added.
MHT-CET 2024
Q90. Identify a compound having highest thermal stability.
Solution: For XX' type interhalogen compounds, stability generally decreases as the electronegativity difference between the two halogens decreases. ClF has the highest bond strength and thermal stability among the options provided.
MHT-CET 2024
Q91. What is the number of lone pair of electrons involved in IF molecule?
Solution: In the diatomic interhalogen IF, Iodine is the central atom with 7 valence electrons. It uses 1 electron for the covalent bond with Fluorine. The remaining 6 electrons exist as 3 lone pairs on the Iodine atom.
MHT-CET 2024
Q92. Which from following compounds is NOT in solid state at 25°C?
Solution: At standard room temperature (25°C), ICl and IBr are solids, and IF3 is an unstable solid. IF5 (Iodine pentafluoride) is a liquid under these conditions.
MHT-CET 2024
Q93. Which from following compounds is most covalent?
Solution: According to Fajan's rules, covalent character increases with the oxidation state of the cation. In SnCl4, Tin is in the +4 oxidation state, making it more covalent than compounds where the metal is in +2 or +3 states.
MHT-CET 2024
Q94. Which among the following P-block elements forms colourless and odourless hydride?
Solution: Oxygen forms water (H2O), which is a colourless and odourless liquid/gas. Ammonia (Nitrogen) has a pungent smell, while H2S (Sulphur) and H2Se (Selenium) have characteristic foul odours.
MHT-CET 2024
Q95. Which element from following has largest atomic size as compared to other three?
Solution: Atomic size increases down a group due to the addition of new electron shells. In Group 16, the order of atomic size is O < S < Se < Te. Therefore, Tellurium is the largest.
MHT-CET 2024
Q96. What is the number of moles of water molecules present in a mole of carnallite?
Solution: The formula for the mineral carnallite is KCl·MgCl2·6H2O. This indicates there are 6 moles of water of crystallization per mole of the compound.
MHT-CET 2024
Q97. Identify a compound having properties of tear gas.
Solution: Tear gas, specifically Chloropicrin, has the chemical formula CCl3NO2. COCl2 is phosgene and the sulfur compound in option C is mustard gas.
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